Literary award · since 1992
Bradbury Award
American literary award. Established 1992.
About Bradbury Award
The Ray Bradbury Nebula Award for Outstanding Dramatic Presentation (formerly the Ray Bradbury Award for Outstanding Dramatic Presentation) is given each year by the Science Fiction and Fantasy Writers Association (SFWA) for science fiction or fantasy dramatic works such as movies or television episodes. To be eligible for Nebula Award consideration a work must be published in English in the United States. Works published in English elsewhere in the world are also eligible provided they are released either on a website or in an electronic edition. Only individual works are eligible, not serials such as television series, though miniseries of three or fewer parts are allowed. The award, named to honor prolific author and screenwriter Ray Bradbury, was begun in 1992 as the Ray Bradbury Award for Outstanding Dramatic Presentation.
From the Wikipedia article “Ray Bradbury Award”, licensed under CC BY-SA 4.0.
Recent winners
| Year | Winner | Winning work |
|---|---|---|
| 2026 | Murderbot | — |
| 2008 | Joss Whedon | — |
| — | J. Michael Straczynski | — |
| — | Babylon 5 | — |
| — | Neill Blomkamp | — |
| — | Terri Tatchell | — |
| — | Christopher Nolan | — |
| — | Dune: Part Two | — |
| — | Benh Zeitlin | — |
| — | Alfonso Cuarón | — |
| — | Jonás Cuarón | — |
| — | Daniels | — |
| — | Greta Gerwig | — |
| — | Denis Villeneuve | — |
From Wikidata; the list may be incomplete for some years.
Eligibility and entering
Check the official rules of the Bradbury Award for the current eligibility window, accepted formats, residency or language requirements and any entry fee. For most established prizes the publisher submits on the author's behalf, often with a limit on entries per imprint.
If you are self-published, look for an explicit statement that independently published books are accepted, and budget for entry fees and copies for judges.
Sources & data
- Structured data from Wikidata Q3405197 (CC0).
- Summary text from Wikipedia (CC BY-SA 4.0).